Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the
. character does not represent a decimal point and is used to separate number sequences.For instance,
2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
class Solution(object): def compareVersion(self, version1, version2): parts1 = [int(x) for x in version1.split('.')] parts2 = [int(x) for x in version2.split('.')] # fill up the shorter version with zeros ... lendiff = len(parts1) - len(parts2) if lendiff > 0: parts2.extend( * lendiff) elif lendiff < 0: parts1.extend( * (-lendiff)) for i, p in enumerate(parts1): ret = cmp(p, parts2[i]) if ret: return ret return 0